Please how * will take and how count is happening

Programming Python
#1

for x in [0, 1, 1, 3]:
for y in [0, 2, 1, 2]:
print(‘*’)

#2

You may want to paste your code in a

code block
    which preserves
         indentation

Just use the </> button to create the block.

Not clear what your question is: the code, if I understand how it was supposed to be indented, doesn’t really do anything interesting. It just prints 16 * characters, one per line.

#3

it’s an indentation error in line2, line3 , the output of this coad is 16*

#4

Your code is using nested iteration that must be written as below:

for x in [0, 1, 1, 3]:
    for y in [0, 2, 1, 2]:
        print('*')

So, * will take as for each x element 4 y elements. In elaboration it’s like:

for x=0 > 
        y=0
           print('*')           Next>
        y=2
           print('*')           Next>
        y=1
           print('*')           Next>
        y=2
           print('*')           Next> 
for x=1 >
        y=0
           print('*')           Next>

So on … till x=3 & y=2

Hence, * will be printed 16 times.

Hope, this helps!
Thanks.