Hi, with this question. I understand that i starts at 5 and during the loop it will add 1 each time and it will break when this gets met. i%0o11 == 0: However I don’t understand what this means. Can someone explain?

I have added comments to the code to help:

```
i = 5
while True: # This starts an infinite loop.
if i % 0o11 == 0: # This line checks if i is divisible by 9 (octal 11 is decimal 9) with no remainder.
break # If i is divisible by 9, exit the loop.
print(i) # Print the current value of i.
i += 1 # Increment i by 1.
```

The octal number `0o11`

in Python is equivalent to the decimal number `9`

. Therefore, the condition `i % 0o11 == 0`

checks if `i`

is divisible by `9`

with no remainder.

When `i`

becomes `9`

, the `if`

statement’s condition will be true, the `break`

statement will be executed, and the loop will terminate.

Hence, the output will be `5, 6, 7, 8`

printed on separate lines.

How do I know what the decimal equivalent of an octal number is? Should I know all of them off by heart? and which part of the Python course covers this so I can review it.

You can use a programmers calculator or look it up. Though it is good to have some knowledge of hexadecimal and octal numbers.

@Layla If you’re still having difficulty with these numbers, please read this page which should make it clearer.