Hi, with this question. I understand that i starts at 5 and during the loop it will add 1 each time and it will break when this gets met. i%0o11 == 0: However I don’t understand what this means. Can someone explain?
I have added comments to the code to help:
i = 5
while True: # This starts an infinite loop.
if i % 0o11 == 0: # This line checks if i is divisible by 9 (octal 11 is decimal 9) with no remainder.
break # If i is divisible by 9, exit the loop.
print(i) # Print the current value of i.
i += 1 # Increment i by 1.
The octal number 0o11 in Python is equivalent to the decimal number 9. Therefore, the condition i % 0o11 == 0 checks if i is divisible by 9 with no remainder.
When i becomes 9, the if statement’s condition will be true, the break statement will be executed, and the loop will terminate.
Hence, the output will be 5, 6, 7, 8 printed on separate lines.
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How do I know what the decimal equivalent of an octal number is? Should I know all of them off by heart? and which part of the Python course covers this so I can review it.
You can use a programmers calculator or look it up. Though it is good to have some knowledge of hexadecimal and octal numbers.
@Layla If you’re still having difficulty with these numbers, please read this page which should make it clearer.